Core algebra skill

Solving Linear Equations

Learn a reliable process for one-variable linear equations, including fractions, parentheses, and variables on both sides, then verify by substitution.

How this page is maintained

Written for learners, checked against the sources below, and reviewed every year. Last reviewed July 22, 2026.

Short answer

To solve a linear equation, simplify each side, move variable terms to one side, move constants to the other side, then isolate the variable using inverse operations. Check your result by substituting it back into the original equation.

  • Do the same operation to both sides to preserve equality.
  • Clear fractions early when it reduces arithmetic errors.
  • Always verify by substitution in the original equation.

Use structure before arithmetic

A linear equation has the variable raised only to the first power. Before moving terms, distribute parentheses and combine like terms on each side. This reduces noise and helps you avoid moving the wrong terms.

If denominators are simple and common, multiplying both sides by the least common denominator can remove fractions. That often makes the equation faster to solve and easier to check.

Recognize one solution, no solution, or infinitely many

Some equations simplify to a true statement such as 5 = 5. That means infinitely many solutions. Others simplify to a false statement such as 3 = 8. That means no solution.

  • One solution: final form x = number.
  • No solution: contradiction after simplification.
  • Infinitely many: identity after simplification.

Solve an equation with fractions

A student solves (x/3) + 2 = (5x/6) - 1 during homework review.

  1. Multiply both sides by 6 to clear denominators: 2x + 12 = 5x - 6.
  2. Move x terms to one side: 12 = 3x - 6.
  3. Add 6 to both sides: 18 = 3x, then divide by 3: x = 6.
  4. Check in the original equation to confirm both sides are equal.
Result: The solution is x = 6.

Common mistakes

  • Adding a term to one side but forgetting to add it to the other side.
  • Combining unlike terms such as 3x + 2 into 5x.
  • Dropping negative signs when moving terms.
  • Skipping the substitution check and missing arithmetic errors.

Try one

Solve 4(x - 2) + 3 = 2x + 9.

Distribute and simplify: 4x - 8 + 3 = 2x + 9, so 4x - 5 = 2x + 9, then 2x = 14, so x = 7.

Sources

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